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Example research essay topic: Test Tube First Four - 2,315 words

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Introduction: Qualitative Qualitative Analysis Qualitative Analysis Introduction: Qualitative analysis is used in the determination of the identity of a substance. It is different from quantitative analysis, which deals with the determination of the amount of a substance. In this experiment, qualitative analysis techniques are used to determine whether or not a sample contains a certain ion. When using this method, an unknown and a reactant are mixed.

The result of the reaction leads to a conclusion about the presence or absence of certain ions in the unknown. Many ions react in similar ways, and although the addition of one reagent to an unknown may not identify the ion, it limits the possibilities as to what the ion could be. A sequence of reactions used to analyze a sample is called a scheme, and it usually requires a large number of reagents and separation steps. For this experiment, the unknown may contain anywhere from 2 to all of the following cations and anions: Cations Anions Ag+Cl- Ba 2 +SO 42 - Fe 3 +PO 43 - Cu 2 + Cr 3 + The following reagents are used to identify the ions SO 4 2 M HCl 2 M NH 4 OH (labeled as NH 4 +) 2 M NaOH. 1 M Ba (NO 3) 2 (labeled as. 1 M Ba 2 +). 1 M Ag NO 3 (labeled as. 1 M Ag+) The first four are used to identify the cations, and the last two, used in conjunction with the first four, are used to identify the anions.

The identification of the ions is mainly based on solu bilities. This means that something must be known about the solubility characteristics of the different ions in the presence of the available reagents. The point of the first part of the experiment is to learn which reagents cause the ions to form precipitates, and which reagents dissolve the precipitates formed by the ions. This information is used to make the flow charts for the identification on the unknown ions. For example, it is important to know that a certain reagent will dissolve the precipitate formed by one ion, while it will not dissolve the precipitate formed by another ion. This can be used to distinguish between two different precipitates present in a solution, or to confirm which ion formed the precipitate and therefore was present in the solution.

When carrying out the reactions, avoid adding an excess of reagent to the solution. This is because some precipitates redissolve in an excess of the reagent. Therefore, in cases where one drop of reagent produces a precipitate, 3 or more drops could completely dissolve the precipitate without it ever being visible to the eye. This would cause a large error in the scheme developed to identify the unknown ions. Experimental: The first part of the experiment consists of reacting the cations and anions with the reagents in order to see what the reaction will result in (precipitate or no precipitate). The cations were each reacted with the first four reagents listed in the introduction (H 2 SO 4, HCl, NH 4 +, and NaOH).

Then, the anions were each reacted with Ba 2 + and Ag+. This was done by placing 2 drops of the ion in the test tube and then adding 2 drops of reagent. Each cation was reacted with each of the 4 reagents before moving on to the next cation to be tested. Prior to performing the reactions, a chart was made like the one in the data and calculations section.

As each reaction was performed, the chart was filled in with the observation of what happened. If there was no change, NR was written in the chart for? no reaction. ? If a precipitate formed, the color of the precipitate was written in the chart. If there was no precipitate but there was a color change in the solution, that was also recorded. As each reaction was carried out, it was sometimes difficult to determine whether a precipitate formed or not.

If there was uncertainty, the test tubes had to be placed into the centrifuge in order to separate the precipitates from the solution. There are some very important things to remember when using the centrifuge. First, when tubes are placed in the centrifuge, a tube with an approximately equal volume of solution should be placed exactly opposite each sample tube to counterbalance it (use a test tube filled with an equivalent amount of water if necessary). Second, the centrifuge should come to a stop before it is opened and the test tubes removed.

This is to avoid injury. Once the tubes were removed from the centrifuge, it was obvious whether there was a precipitate present or not. If a solid has settled onto the bottom or side of the test tube, there was a precipitate present. If the tube appears to contain the same solution as before the test tube was placed in the centrifuge, no reaction occurred. The next part of the experiment consists of determining which reagents dissolve certain precipitates.

This information can be especially helpful when determining the ions present in the unknown. The precipitates tested were Ag Cl, Ba SO 4, and Ag 3 (PO 4). They were reacted with HCl, H 2 SO 4, NH 4 OH, and NaOH. This was done by making the precipitate using the information from the first chart, and then adding 2 drops of reagent. For example, the precipitate Ag Cl was made by reacting Ag+ with HCl. Four samples of this were prepared, and each of the reagents was added to the samples to see if the precipitate dissolved.

A chart was filled in with the results of the reactions. In the final part of the experiment, the unknown was tested to determine which ions were present in it. This was done using flow charts created with the information from part 1 of the experiment (see data and calculations section). To test for the ions in unknown # 2, it was first made into a solution by adding 25 mL of distilled water to the sample in a 100 mL beaker. It was mixed until all of the solid dissolved. To speed up the dissolving process, the beaker was held in the palm of the hand in order to slightly heat the solution.

Once the solution was ready, it was tested for the ions by following the flow charts. For each step, 2 drops of reagent was added to 2 drops of unknown solution. To test for the cations, the cation flow chart was followed. First, HCl was added to the solution. There was no reaction, so H 2 SO 4 was added to another sample of the unknown solution. This also resulted in no reaction, so NaOH was added to another sample of the solution.

A rusty-brown precipitate appeared, which meant either PO 43 - or Cu 2 + was present. To determine which one of these ions was present, NH 4 + was added to the solution, and a rust-colored precipitate formed. This confirmed the presence of Fe 3 +. Next, the unknown had to be tested for anions. The anion flow chart was followed. 2 drops of unknown were reacted with Ba 2 +, and there was no reaction. 2 more drops of unknown were reacted with Ag+, and white and tan precipitates formed. H 2 SO 4 was added to the test tube containing the precipitates, and a white precipitate was left.

This confirmed that PO 43 - was present but dissolved when the H 2 SO 4 was added (as was found in part 1 of the experiment), leaving the Cl-. Therefore, the anions present were Cl- and PO 43 -. Data and Calculations: The data charts and the flow charts are on the following pages. Unknown # 2 contains Fe 3 +, Cl-, PO 43 -. Net ionic equations for precipitates and reactions on flow charts: Ag+ + Cl-? Ag Cl Ba 2 + + SO 42 -?

Ba SO 4 Fe 3 + + 3 OH-? Fe (OH) 3 Cu 2 + + 2 OH-? Cu (OH) 2 Cr 3 + + 3 OH-? Cr (Ag+ + PO 43 -? Ag 3 (PO 4) Ag 3 (PO 4) + H 2 SO 4? Ag 2 (SO 4) + H 3 PO 4 Thought process for flow charts: 2 separate flow charts had to be made, one for the cations and one for the anions.

Starting with the cations, the flow chart must begin by listing all cations possibly present because the unknown can contain any number of them. HCl was the first reagent added on the flow chart because it only produced a precipitate with one of the cations, Ag+. This was determined using the data chart from part 1 of the experiment, where the precipitates formed with each reagent were clearly delineated. By beginning the flow chart with reagents that produce fewer precipitates and ending it with the ones that produce more, the chart was easier to follow during the testing for ions.

Therefore, the next reagent used on the chart was H 2 SO 4. Since the Ag+ precipitated out as Ag Cl, the ions left to react with H 2 SO 4 were Ba 2 +, Fe 3 +, Cu 2 +, and Cr 3 + (these were the ions that were left unrelated by the HCl). By referring to the data chart from part 1 of the lab, it was found that H 2 SO 4 only formed a precipitate with Ba 2 + (Ba SO 4). This meant that the Fe 3 +, Cu 2 +, and Cr 3 + ions were left unrelated.

NaOH was added to these ions and it formed a rust-colored precipitate with Fe 3 +, while it formed a blue precipitate with Cu 2 +. To confirm whether the precipitate was from Fe 3 + or Cu 2 +, NH 4 + was added to the unknown. If a rusty-brown precipitate appeared, the ion present was Fe 3 + (Fe (OH) 3). If no precipitate formed but the solution turned dark blue, Cu 2 + was present. The only ion left unrelated after the NaOH was added was Cr 3 +. If a bluish-white precipitate formed when NH 4 + was added to the Cr 3 +, it confirmed the presence of Cr 3 + (Cr (NH 4) 3).

The anion flow chart began with all three of the anions listed (SO 42 -, Cl-, PO 43 -). Ba 2 + was the first reagent added because it formed a precipitate with only one of the ions, SO 42 - (Ba SO 4). The ions left unrelated were Cl- and PO 43 -. Ag+ was added to these. At this point, a white precipitate could form with Cl- (Ag Cl), or a yellow precipitate could form with PO 43 - (Ag 3 (PO 4) ). If the precipitate was purely white, the ion was Cl-.

This was confirmed by adding H 2 SO 4 to the precipitate, which would result in no reaction. This is because H 2 SO 4 does not dissolve Ag Cl (from part 1 of the experiment). Then, the addition of NH 4 + would dissolve the precipitate and prove that only Cl- was present. However, if the unknown contained both Cl- and PO 43 -, both precipitates would form, but the two colors of the precipitates would be indistinguishable from each other.

A yellow precipitate would be seen, but it would be impossible to tell if there was also a white precipitate present. Therefore, H 2 SO 4 would again be added to the precipitates. If a white precipitate appeared, it would mean that PO 43 - had been present, but it was dissolved by the H 2 SO 4. It would leave only the Ag Cl precipitate visible (H 2 SO 4 dissolves Ag 3 (PO 4), but not Ag Cl), but because the precipitate originally had a yellow color to it, it would be known that both the Cl- and the PO 43 - ions were present in the unknown solution. If the solution had no precipitate left (turned clear) when the H 2 SO 4 was added to the yellowish precipitate, it would indicate that only PO 43 - was present in the solution. This is because H 2 SO 4 dissolves Ag 3 (PO 4), and there were no other precipitates left in the solution to be seen.

Results and Discussion: In conclusion, unknown # 2 contained Fe 3 +, Cl-, PO 43 -. This was determined using qualitative analysis, and the purpose of the experiment was therefore fulfilled. One possible source of error for this lab could occur in part 1, where the reactions of different reagents with different ions are recorded in data charts. If there is incorrect information about whether or not a precipitate formed, it will most likely result in an incorrect flow chart and an incorrect identification of the ions in the unknown.

That is why it is important to use the centrifuge if there is uncertainty about a precipitate, or the reaction should be performed again. Another source of error would be to add too many drops of reagent to the ion or sample of unknown. This is because a precipitate may form with the reagent, but dissolve in an excess of the reagent. Therefore, the precipitate could form but then be dissolved without ever being seen.

This would also result in an incorrect flow chart and an incorrect identification of the unknown ions. Another source of error could occur in making or following the flow chart. Incorrect reasoning when designing the flow chart will make it difficult to correctly identify the ions in the unknown, and not following the flow chart correctly would obviously cause error in the final results.


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