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Statistics. Suppose you have 3 nickels, 2 dimes, and 6 quarters in your pocket. Total population of coins: 3 + 2 + 6 = 11. If you draw a coin randomly from your pocket, what is the probability that: a. You will draw a dime? Probability is 2 / 11 b.
You will draw a half-dollar? Probability is 0 / 11 if you draw only one coin (there are no half dollars). c. You will draw a quarter? Probability is 6 / 11 2. You are rolling a pair of dice, one red and one green.
What is the probability of the following outcomes: a. The sum of the two numbers you roll from the dice is 11. S = }. S = }. Total combinations = 36 11 can be obtained only if one dice gets either 5 and the other one gets 6 or the one gets 6 and the other one gets 5. 2 / 36 + 2 / 36 = 4 / 36 = 1 / 9. so there is a chance that for each eighteen times you throw a dice you might get 11.
b. The sum of the two numbers you roll is 7. you can get 7 by using 6 combinations of 2 dice. Thus the probability is 6 / 36 = 1 / 6 = 0. 16 c. The sum of the two numbers you roll is 13. Probability is 0 (zero).
For this question pretend you are drawing cards without replacement from the infamous "Iraq's Most Wanted" deck issued by the U. S. Military. If you are drawing from the full deck of 55 cards, what are the following probabilities: a.
You draw a card that is not Saddam Hussein Hussein can be 1 / 55, so Not-Hussein is 54 / 55 chance. b. You draw three cards, which end up being Saddam Hussein and his two sons. First is Saddam: there are 1 / 55 + 1 / 54 + 1 / 53 = 0. 0555 chance that he and his 2 sons are picked.
Each card is equally likely to be picked, each with each drawing, the total number of cards declines thus the chances of getting the third card are more likely than the chances of getting the first or second card. c. You draw 14 cards and not one of them is Saddam Hussein [note: this is a tough one, remember to show your work. In order to understand the chances of Saddam not being chosen, one has to get the understanding of the chances of him being chosen and then subtract these chances from 1 (total probability) to obtain the chances of him not chosen. Thus we can estimate that initially he had 1 / 55 chance of being picked, than the chances would increase to 1 / 54, 1 / 53, 1 / 52... 1 / 41 (after all 14 tries). After adding up the array of these figure we get a chance of 0. 31506 that Saddam will be chosen after all 14 cards are drawn.
On the contrary, there is a 0. 68494 (1 - 0. 31506) chance that we will draw 14 cards and none of them is Saddam.
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